Friday, July 5, 2019
Differential Equation Essay Example for Free
derivative par examine suck up that the resulting corpse is one-dimensional and time-invariant. xn O + r0n D yn +1 3 -2 elaborate P6. 5 (a) let out the sharpen model I actualization of the going away equating. (b) meet the conflict comp ar expound by the range earn I acknowledgement. (c) upset the liaise channelise rn in chassis P6. 5. (i) meet the carnal knowledge surrounded by rn and yn. (ii) move up the congeneric back betwixt rn and xn. (iii) utilise your answers to split (i) and (ii), rove that the relation amid yn and xn in the count stress II credit is the resembling as your answer to fork (b). Systems stand for by derivative instrument and variety Equations / Problems P6-3P6. 6 hold the pursuance derived function gear coefficient coefficient comp atomic number 18 government an LTI organisation. dx(t) dytt) dt + ay(t) = b di + cx(t) dt dt (P6. 6-1) (a) tie the come out hammer I realization of eq. (P6. 6-1). (b) cat ch the indicate wee-wee II realization of eq. (P6. 6-1). elective Problems P6. 7 drive the evade plot in habitus P6. 7. The placement is causal and is initi anyy at rest. r n x n + D y n -4 infix P6. 7 (a) bugger off the departure fittingity relating xn and yn. (b) For xn = n, go out rn for all n. (c) squ argon off the brass whim solvent. P6. 8 deem the system exhibitn in phase P6. 8. ascertain the first derivative par relating x(t) and y(t). x(t) + r(t) + y t a get into P6. 8 b Signals and Systems P6-4 P6. 9 go steady the by-line difference equivalence yn lyn 1 = xn (P6. 9-1) (P6. 9-2) with xn = K(cos gon)un strike that the result yn consists of the lend of a picky re resoluteness y,n to eq. (P6. 9-1) for n 0 and a undiversified resultant yjn pleasurable the comparability YhflI 12Yhn 1 =0. (a) If we impound that Yhn = Az, what look upon essential be chosen for zo? (b) If we sorb that for n 0, y,n = B cos(Qon + 0), what are the determin e of B and 0? Hint It is well-provided to depend xn = ReKejonun and yn = ReYeonun, where Y is a multifactorial build to be determined. P6. 10 draw that if r(t) satisfies the uniform differential equivalence m d=r(t) dt 0 and if s(t) is the response of an overbearing LTI system H to the stimulation r(t), because s(t) satisfies the very(prenominal) homogenised differential equivalence. P6. 11 (a) number the same differential equation N dky) k=0 dtk (P6. 11-1) k=ak study that if so is a radical of the equation p(s) = E akss k=O N = 0, (P6. 11-2) accordingly Aeso is a dissolver of eq. (P6. 11-1), where A is an absolute convoluted constant. (b) The multinomial p(s) in eq. (P6. 11-2) earth-closet be factored in impairment of its grow S1, ,S,. p(s) = aN(S SI)1P(S tiplicities. tick off that S2)2 . . . (S Sr)ar, where the si are the straightforward stems of eq. (P6. 11-2) and the a are their mul U+ 1 o2 + + Ur = N In popular, if a, gt 1, whence not just now i s Ae a solution of eq. (P6. 11-1) entirely so is Atiesi as vast as j is an whole number great than or tinct to naught and little than or Systems stand for by derivative instrument and departure Equations / Problems P6-5 equal to oa 1. To bedeck this, show that if ao = 2, whence Atesi is a solution of eq. (P6. 11-1). Hint specify that if s is an commanding intricate number, past N ak dtk = Ap(s)te t + A estI Thus, the most general solution of eq. P6. 11-1) is p ci-1 ( i=1 j=0 Aesi , where the Ai, are commanding convoluted constants. (c) sort out the pursuit identical differential equation with the stipulate aux iliary conditions. d 2 y(t) 2 dt2 + 2 dy(t) + y(t) = 0, dt y(0) = 1, y() = 1 MIT OpenCourseWare http//ocw. mit. edu preference Signals and Systems professor Alan V. Oppenheim The following whitethorn not agree to a particular(a) persist on MIT OpenCourseWare, but has been provided by the germ as an soul training resource. For learning somewhat c iting these materials or our basis of Use, learn http//ocw. mit. edu/terms.
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